0
What else can I help you with?
What is the greatest common factor of 4a2 2a?
2a
How do you factor 4a2 -4a - 120?
(2a + 10)(2a - 12)
What is the HCF of 4a and 10a?
The GCF is 2a.
What is the GCF of 4a and 10a?
The greatest common factor (GCF) of 4a and 10a is 2a. To find the GCF, we need to identify the largest factor that both 4a and 10a have in common. In this case, both 4a and 10a can be divided by 2 and a, making 2a the greatest common factor.
In which situation would you factor out -1 from a trinomial?
You would factor out -1 (a) from a trinomial in an equation such as -a^2 +30a - 2a + 60 after the middle term has been separated. The final answer of this trinomial would then be (a-30) (a-30).
How do you solve for x using a quadratic equation?
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
Is a plus 2a equals 3a equation or expression?
It is, in fact, an identity - which is an equation which is true for all values of the variable.
What is the answer to -2a plus y?
They are two terms of an algebraic expression which can be arranged as : y-2a
When plotting points for graphing a quadratic equation be sure to choose values of x that are greater than and less than the value of x in the?
from the equation using the formula -b/2a to find x value. from there substitute values of x before and after in equation.for example if x is 2 use other x values as 1 and 3.
How do you find the vertex of an equation in standard form?
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
The equation for the axis of symmetry is?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
If 2a-3b11 and ab7 find the value of a and b?
I take it you mean if 2a - 3b = 11 an a+b = 7 then find the value of a and b. The problem with this site is that the questions can't contain things like the equal sign To solve a problem like this we need to get two of the letter values to be the same, and then we can subtract one equation from the other. so, if we multiply the second equation by -2 we get -2a - 2b = -14 No to that we add 2a - 3b = 11 and we get -5b = -3 so b = 3/5 Now we can replace the b in the second equation and we get a + 3/5 = 7 So we can see that a must equal 62/5 and if we put these values into the first equation the two sides of the equation should balance... 2 (62/5) - 3(3/5) should equal 11... so we'll multiply the values and check 2 (62/5) = 124/5 and 3(3/5) = 9/5 = 14/5 and indeed 124/5 - 14/5 does indeed = 11.
How do you find the roots of an equation?
for an 2nd order the roots are : [-b+-sqrt(b^2-4ac)]/2a
What is the mathimatical equation a x a simplified to?
The answer is 2a because of the two a's equal 2a
What is the equation 2a-b3?
Firstly, I think you mean 2a-3b. The numbers always come first. Secondly, 2a-3b is an expression, not an equation as equations have equeal signs in them. Lastly, you do not have enough information to solve 2a-3b since it is an expression. Therefore, the answer to your question is 2a-3b.
Why is the equation of the line of symmetry x equals negative b over 2a?
The question refers to the equation of a parabola, that is, a quadratic equation of the form y = ax2 + bx + c. Suppose x1 = -b/2a - z and x2 = -b/2a + z for some real number z. Then y1 = a*(-b/2a - z)2 + b*(-b/2a - z) + c = b2/4a + bz + az2 - b2/2a - bz + c = b2/4a + az2 - b2/2a + c and y2 = (-b/2a + z)2 + b*(-b/2a + z) + c = b2/4a - bz + az2 - b2/2a + bz + c = b2/4a + az2 - b2/2a + c So y1 = y2 thus, if x is the same distance (z) either side of -b/2a, then the corresponding y values are the same. And that, is what a line of symmetry means.
What is the equation for the axis of symmetry of a parabola?
x=-b/2a [negative B over 2A]
