2K + Cl2 --> 2KCl
Using the discriminant for a quadratic equation the value of k works out as plus or minus 12.
k added to 2.5
It is a linear equation in the variable r.
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.
The equation you provided appears to be incorrectly formatted. However, if you meant to write the standard form of a circle's equation, which is ((x - h)^2 + (y - k)^2 = r^2), then the center of the circle is given by the point ((h, k)). For the specific equation you intended, please clarify the format, and I can help identify the center accordingly.
2K(s) + Cl2(g) → 2KCl(s)
Ca + Cl2 ----> CaCl Step 1) Ca + Cl2 ----> 2 CaCl There are 2 Cl's on the reaction side so you need 2 on the Product side Step 2) 2Ca + Cl2 ----> 2 CaCl There are now 2 Ca on the product side and you need 2 on the reactant side Voila!
The chemical equation is:2 K + Cl2 = 2 KCl
k equals 5.6
Yes, the equation K + Br2 = KBr is a balanced chemical equation. For example, 2 K + Br2 = 2 KBr is one and another balance chemical equation is Fe + Cl2 = FeCl3.
A line in the X-Y plane follows an equation y = (slope X x) plus a constant k. In this instances, 5 = [(-12)(3)] + k, or k = 5 + 36 = 41. Therefore, the equation is: y = -12x + 41.
2 K + Br2 -> 2 Kbr
Balanced :2 K + 2 H2O ----> 2 KOH + H2
Using the discriminant for a quadratic equation the value of k works out as plus or minus 12.
The equilibrium constant (K eq) for the reaction 2HCl(g) ⇌ H2(g) + Cl2(g) would be [H2][Cl2]/[HCl]^2, where the square brackets indicate the molar concentrations of the respective species at equilibrium.
A number, k, increased by two and a half.
k added to 2.5