A line in the X-Y plane follows an equation y = (slope X x) plus a constant k. In this instances, 5 = [(-12)(3)] + k, or k = 5 + 36 = 41. Therefore, the equation is:
y = -12x + 41.
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Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
The point slope equation is (y - 9) = 5*(x - 4)
-7