A line in the X-Y plane follows an equation y = (slope X x) plus a constant k. In this instances, 5 = [(-12)(3)] + k, or k = 5 + 36 = 41. Therefore, the equation is:
y = -12x + 41.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
The point slope equation is (y - 9) = 5*(x - 4)
-7
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
write an equation that has a slope 7 and passes through the point (2,17)
The slope intercept form through 23 and 15 would be 5. This is considered as a math equation.
The equation of a line with an undefined slope is x = a.
slope 5/6 through (-18,6)
It is: y = 5x+6
Coordinate geometry
you say undefined
The answer is: y = 1/2x + 4
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
-12