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A line in the X-Y plane follows an equation y = (slope X x) plus a constant k. In this instances, 5 = [(-12)(3)] + k, or k = 5 + 36 = 41. Therefore, the equation is:

y = -12x + 41.

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Q: Write the point-slope equation of the line that goes through 5 3 with a slope of -12?
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