To find the slope-intercept form of the equation of a line parallel to ( y = 9x + 1 ) and passing through the point (1, 4), we first note that parallel lines have the same slope. The slope of the given line is 9. Using the point-slope form ( y - y_1 = m(x - x_1) ), we plug in the point (1, 4) and the slope 9:
[ y - 4 = 9(x - 1) ]
Simplifying this gives:
[ y = 9x - 5 ]
Thus, the slope-intercept form of the new line is ( y = 9x - 5 ).
If you mean y = -65x-4 then the parallel equation is y = -65x-66
Any equation parallel to the x-axis is of the form:y = constant In this case, you can figure out the constant from the given point.
The equation of a line that is parallel to ( y = 5 ) will have the same slope, which is 0, indicating a horizontal line. Since it passes through the point (4, 7), the equation of the line is simply ( y = 7 ).
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
An equation of a line that is parallel to the y-axis is a vertical line. For a vertical line that passes through the coordinate (2, 4), the equation is simply x = 2. This means that for any value of y, the x-coordinate remains constant at 2.
The parallel equation will have the same slope but with a different y intercept
If you mean: y = 2x-4 and (1, 5) then the parallel equation is y = 2x+3
If you mean: y = 6x-4 then the parallel equation is y = 6x+10
If you mean y = -65x-4 then the parallel equation is y = -65x-66
If you mean y = -4x+1 and (2, 1) then the parallel equation is y = -4x+9
Known equation: 3x+5y = 6 or y = -3/5x +6/5 Slope of equation: -3/5 Slope of parallel equation: -3/5 Parallel equation: y-1 = -3/5(x-3) => 5y = -3x+14 Parallel equation in its general form: 3x+5y-14 = 0
Any equation parallel to the x-axis is of the form:y = constant In this case, you can figure out the constant from the given point.
Any equation parallel to the x-axis is of the form:y = constant In this case, you can figure out the constant from the given point.
The equation of a line that is parallel to ( y = 5 ) will have the same slope, which is 0, indicating a horizontal line. Since it passes through the point (4, 7), the equation of the line is simply ( y = 7 ).
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
y -x + 1