y -x + 1
11 times 4 1times 44
Assume the equation is: 5x = 2y + 44;then y = (5/2) x - 22This is a straight line with slope 5/2, andintercepting the y axis at the point (0, -22)
5x2 - 136 = 44 5x2 - 136 + 136 = 44 + 136 5x2 = 180 5x2/5 = 180/5 x2 = 36 √x2 = √36 x = ±6
It is: y-4 = 9(x-5) => y = 9x-41 Or as: 9x-y-41 = 0. Another version of the standard form of a linear equation in coordinates x and y is y = s x + k, where s is the slope and k is a constant. In this question, the slope s is directly given, as is the value of y at the point where x = 5 so that- 44. The slope is always the coefficient of x in this standard form, and the constant k can be determined by solving the equation for the coordinates of the given point: When x = 5, y = (9 X 5) + k, and y(5) is stated by the question to be 4. 9 X 5 equals 45; therefore to obtain the right value for k, 45 + k =4 or k = - 41. The standard form of the equation is therefore y = 5x - 41.
Divide 1 by 44: 1 / 44 = 0.023 (rounded)
It is the parallel of latitude that runs 66° 33′ 44″ (or 66.5622°) north of the Equator.
-10
London is on the 44 degree Parallel. 51 degrees north surely!!
11 times 4 1times 44
the answer is D. page 44
44 = 80*x
x+>44
30131
Assume the equation is: 5x = 2y + 44;then y = (5/2) x - 22This is a straight line with slope 5/2, andintercepting the y axis at the point (0, -22)
The parallel of latitude that runs 66° 33′ 44″ (or 66.5622°) north of the Equator.
A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............
p = 3209/44