y -x + 1
11 times 4 1times 44
Assume the equation is: 5x = 2y + 44;then y = (5/2) x - 22This is a straight line with slope 5/2, andintercepting the y axis at the point (0, -22)
5x2 - 136 = 44 5x2 - 136 + 136 = 44 + 136 5x2 = 180 5x2/5 = 180/5 x2 = 36 √x2 = √36 x = ±6
It is: y-4 = 9(x-5) => y = 9x-41 Or as: 9x-y-41 = 0. Another version of the standard form of a linear equation in coordinates x and y is y = s x + k, where s is the slope and k is a constant. In this question, the slope s is directly given, as is the value of y at the point where x = 5 so that- 44. The slope is always the coefficient of x in this standard form, and the constant k can be determined by solving the equation for the coordinates of the given point: When x = 5, y = (9 X 5) + k, and y(5) is stated by the question to be 4. 9 X 5 equals 45; therefore to obtain the right value for k, 45 + k =4 or k = - 41. The standard form of the equation is therefore y = 5x - 41.
Divide 1 by 44: 1 / 44 = 0.023 (rounded)
It is the parallel of latitude that runs 66° 33′ 44″ (or 66.5622°) north of the Equator.
To find the equation of the line perpendicular to (y - 4x + 2 = 0), we first determine the slope of the given line, which is 4. The slope of the line perpendicular to it will be the negative reciprocal, (-\frac{1}{4}). Using the point (4, 4) and the point-slope form of the equation (y - y_1 = m(x - x_1)), we have: [ y - 4 = -\frac{1}{4}(x - 4). ] This simplifies to (y = -\frac{1}{4}x + 5).
-10
London is on the 44 degree Parallel. 51 degrees north surely!!
11 times 4 1times 44
the answer is D. page 44
44 = 80*x
30131
Assume the equation is: 5x = 2y + 44;then y = (5/2) x - 22This is a straight line with slope 5/2, andintercepting the y axis at the point (0, -22)
To graph the equation (-2 \leq 2x - 44), first, you can rearrange it to isolate (x): add 44 to both sides to get (42 \leq 2x), then divide by 2, giving (21 \leq x) or (x \geq 21). This represents a vertical line at (x = 21) on the graph, with a solid line indicating that (x) can equal 21. Shade the region to the right of this line to show all values of (x) that satisfy the inequality.
The parallel of latitude that runs 66° 33′ 44″ (or 66.5622°) north of the Equator.
To find the number of 176 Ω resistors needed in parallel to carry 5 A on a 220 V line, first calculate the equivalent resistance (R) using Ohm's law: ( R = V/I = 220 V / 5 A = 44 Ω ). For resistors in parallel, the formula is ( 1/R_{eq} = 1/R_1 + 1/R_2 + ... + 1/R_n ). For n resistors of 176 Ω, this becomes ( 1/R_{eq} = n / 176 ). Setting ( R_{eq} = 44 Ω ) gives ( n = 176/44 = 4 ). Therefore, 4 resistors are required.