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x2 - 6x + 1 = 0

x = [-(-6) +&- square root of [(-6)2 - 4(1)(1)]]/2(1)

x = (6 +&- square root of 32)/2

x = [6 +&- 4(square root of 2)]/2

x = 3 +&- 2(square root of 2)

x = 3 + 2(square root of 2) or x = 3 - 2(square root of 2)

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15y ago
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Q: X2-6x plus 1 equals 0
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