X2-6x plus 1 equals 0

Answer 1

x2 - 6x + 1 = 0

x = [-(-6) +&- square root of [(-6)2 - 4(1)(1)]]/2(1)

x = (6 +&- square root of 32)/2

x = [6 +&- 4(square root of 2)]/2

x = 3 +&- 2(square root of 2)

x = 3 + 2(square root of 2) or x = 3 - 2(square root of 2)

Check: