x=-1
x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2
x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
(4 ± i2) where i2 = -1
(x+ 7)(x + 1) so x = -1 or -7
x=-1
x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2
x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
(4 ± i2) where i2 = -1
(x+ 7)(x + 1) so x = -1 or -7
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4
If that's 8x33, the answer is -x2(8x31 - 1) If that's 8x3, the answer is -x2(8x - 1) If that's 8x - 33, the answer is (x - 11)(x + 3) If that's 8x + 33, the answer is irreducible. Proper notation is important.
The roots are: x = 1 and x = 7 So: 7*1 = 7
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
(1, 1)
1
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0