y = x2 + 8x - 7
a = 1, b = 8, c = -7
the equation of the axis of symmetry: x = -b/2a
x = -8/(2*1) = -4
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
Line of symmetry: x = 3
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
It gets reflected in the x-axis.
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
X=-b/2a
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
Line of symmetry: x = 3
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
Yes, it is a linear equation with no slope. The graph is a straight line (parallel to the x-axis) that passes through the y-axis, at {0,-3}
The is a straight line parallel to the y-axis with an x intercept at -3.
It is the axis of symmetry.
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.