x2 - x - 6 = (x - 3)(x + 2) = 0;
whence, x = 3 or -2.
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-x2 = x - 6 x2 + x - 6 = 0 (x - 2)(x + 3) = 0 x ∈ {-3, 2}
(x + 6)(x - 6)
x2- 7x + 6 = 0 factor, (x-6)(x-1) = 0 x = 6 x = 1
x2 + x - 30 = (x + 6)(x - 5)
Strictly speaking, it is a quadratic equation in x. x2 + x = 6 => x2 + x - 6 = 0 => (x+3)*(x-2) = 0 => x = -3 or x = 2