x2 + 2x = 3
x2 + 2x - 3 = 0
x2 + 2x - 3 = y Graph the equation in a calculator and find its zeros, which are x = -3 and x = 1.
Check:
x2 + 2x = 3
(-3)2 + 2(-3) =? 3
9 - 6 =? 3
3 = 3 True
(1)2 + 2(1) =? 3
1 + 2 =? 3
3 = 3 True
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That's an extraneous solution. You need to check for these when algebraically solving equations, especially when you take both sides of an equation to a power.
-13x = 52 x = -4 Check: -13*-4 = 52
It depends whether it is a subtraction, mulitplication, addition, or division problem.
Set up algebraically. X = what X/2769 = 5 2769/1*(X/2769 = 5)*2769/1 multiply through by 2769 X = 13845 ------------- check 13845/2769 = 5 5 = 5 checks
yes. check: 3x-6=5x-10 2x=4. X=2. yay!