You can check an answer by substituting it into the equation.
x - 17 = 11
25 - 17 = 11
8 = 11
Since this is not true, 25 is not the answer.
No.
It has one real solution.
w=4.5
[ 8x - 2 = 14 ] is the equation.[ x = 2 ] is the solution to the equation.
It is a linear equation in x. The equation has the solution x = 0.
I don't believe it is a solution.
To determine if a point is a solution on a graph, check if the point's coordinates (x, y) satisfy the equation of the graph. If the point lies on the curve or line representing the equation, it is a solution. For instance, if the equation is y = f(x), substitute the x-coordinate into the equation to see if it equals the y-coordinate. If it does, the point is a solution.
r=0 is the solution...
An equation never equals a number, but its solution often does.-- An equation with a solution of six: [ 3x - 14 = 4 ]-- An equation with a solution of three: [ 14 - 10x = -16 ]-- An equation with both solutions: [ x2 - 9x + 20 = 2 ]An equation that equals 6 is 10 - 4 = 6An equation that equals 3 is 10 - 7 = 3
An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.
To determine if 5 is a solution to the equation (7x + 10 = 40), substitute (x) with 5. This gives (7(5) + 10 = 35 + 10 = 45), which does not equal 40. Therefore, 5 is not a solution to the equation.
You would solve for M1, which represents the molarity of the stock solution. The equation M1V1 = M2V2 is used to calculate the molarity of a stock solution when you know the volume and molarity of a more diluted solution.
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
root
one
Possibly the solution to an equation
No.