x^(2) + 3x - 7 = 5x + 8
Subtract '8' from both sides
Hence
x^(2) + 3x - 15 = 5x
Subtract '5x' from both sides
Hence
x^(2) -2x - 15 = 0
It is now in quadratic form and will factor.
Hence
( x -5)(x + 3) = 0
x = 5
& x = -3
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x2 + 3x - 7 = 5x + 8; thus,
x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15
= (x - 5)(x + 3) = 0.
Therefore the solution is
x = 5 or -3.
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
We can't calculate what it equals until we know the value of ' x '.
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
x2 + 5x - 120 can not be factored.