Oh, dude, for this quadratic equation x^2 - 5x + 4 = 0, the solutions are just the roots of the equation. You can find them by either factoring the quadratic or using the quadratic formula. So, like, the solutions are x = 1 and x = 4. Easy peasy lemon squeezy!
5x2-16x+12 = (5x-6)(x-2) when factored with the help of the quadratic equation formula
Doesn't have integer roots. Quadratic formula gives roots as 3.71 and -5.38.
It is a quadratic polynomial.
Yes.
If the equation is 4x squared - 5x + 10 = 0, then you set a = 4, b = -5, c = 10. Replace these numbers in the quadratic formula.
I suggest you use the quadratic formula. In this case, a = 1, b = 5, c = 3.
Oh, dude, for this quadratic equation x^2 - 5x + 4 = 0, the solutions are just the roots of the equation. You can find them by either factoring the quadratic or using the quadratic formula. So, like, the solutions are x = 1 and x = 4. Easy peasy lemon squeezy!
5x2-16x+12 = (5x-6)(x-2) when factored with the help of the quadratic equation formula
Doesn't have integer roots. Quadratic formula gives roots as 3.71 and -5.38.
x2+5x-14 = 0 (x-2)(x+7) = 0 Therefore: x = 2 or x = -7
It is a quadratic expression.
It is a quadratic polynomial.
It can't be expressed in quadratic terms because its discriminant is less than zero.
Yes.
-7 therefore the quadratic equation has no real roots
It is a quadratic equation in the variable x.