Radius = 1111
The ' 1 ' in that equation is the radius.
The circles are concentric with centre (0,0). The radius of the outer circle is sqrt(72), that of the inner circle is sqrt(18). By Pythagoras, the length of the semichord is sqrt(72 - 18) = sqrt(54) units. Therefore the chord is 2*sqrt(54) = 6*sqrt(6) = 14.679 units (approx).
If x^2 plus y^2 = 169 then the center of the circle is at (0, 0) and its radius is the square root of 169 which is 13
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
Radius = 1111
If you mean: x^2 + y^2 = 121 then the radius is the square root of 121 which is 11
X2 + y2 = 100 = r2 r = 10
The ' 1 ' in that equation is the radius.
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
it equals LxL+WxW
sqrt 36 ie 6
The circles are concentric with centre (0,0). The radius of the outer circle is sqrt(72), that of the inner circle is sqrt(18). By Pythagoras, the length of the semichord is sqrt(72 - 18) = sqrt(54) units. Therefore the chord is 2*sqrt(54) = 6*sqrt(6) = 14.679 units (approx).
If x^2 plus y^2 = 169 then the center of the circle is at (0, 0) and its radius is the square root of 169 which is 13
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
7
10 Both the x-intercept (y=0) and the y-intercept (x=0) have a length of 10 units.