Wiki User
∙ 11y ago10
Both the x-intercept (y=0) and the y-intercept (x=0) have a length of 10 units.
Wiki User
∙ 11y agoRadius = 1111
The ' 1 ' in that equation is the radius.
chords inside circles can be any length from the diameter to almost zero length.
The length of the arc of ABC is 22pi. You can get this answer by completing this equation 330/360*24pi, which will give you 22pi.
The circles are concentric with centre (0,0). The radius of the outer circle is sqrt(72), that of the inner circle is sqrt(18). By Pythagoras, the length of the semichord is sqrt(72 - 18) = sqrt(54) units. Therefore the chord is 2*sqrt(54) = 6*sqrt(6) = 14.679 units (approx).
Radius = 1111
The ' 1 ' in that equation is the radius.
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
sqrt 36 ie 6
The length of the arc of ABC is 22pi. You can get this answer by completing this equation 330/360*24pi, which will give you 22pi.
chords inside circles can be any length from the diameter to almost zero length.
The circles are concentric with centre (0,0). The radius of the outer circle is sqrt(72), that of the inner circle is sqrt(18). By Pythagoras, the length of the semichord is sqrt(72 - 18) = sqrt(54) units. Therefore the chord is 2*sqrt(54) = 6*sqrt(6) = 14.679 units (approx).
Circle A has more area than B
8
C=2(3.14)rThis is circumference equation for circles. If you have the circumference, you need to input it into the equation and solve for r. r is the radius of the circle, so to determine the diameter, which is 2 times the length of the radius, you just need to multiply the number you got for r times 2.
The center of a circle is the same for all circles but the length of the radius can change
They are not all the same length. If that was the case all circles would be the same size.