Oh, isn't that a lovely little equation we have here! When you have x cubed minus x squared, you can simplify it by factoring out an x squared, leaving you with x squared times (x - 1). It's like painting a beautiful landscape with just a few brush strokes, bringing out the beauty in the math world.
(x - 5)(x^2 + 1)
You have to put your heart into it!
x(x - 19)(x - 1)
x³ - x² + x - 3 (x² + 1)(x - 1) - 2
x³ + x² - 3x - 3 = (x + 1)(x + √3) (x - √3).
x^(3) - x^(2) - 12x 'x' is a common fractor ' tsker it out. Hence x(x^(2) - x - 12) Factor inside the brackets / x(x - 4(x + 3) Done!!!!!
24
(x - 2)(x^2 + x + 3)
(x - 5)(x^2 + 1)
2x^(3) - 10x^(2) - 12x '2' and 'x' are common factors , so take them out. Hence 2x(x^(2) - 5x - 6) Factor inside the brackets . 2x(x - 6)(x + 1) Done !!!!
You have to put your heart into it!
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1
x(x - 19)(x - 1)
Factor out the GCF and get X(X2-X+1).
x³ - x² + x - 3 (x² + 1)(x - 1) - 2
x³ + x² - 3x - 3 = (x + 1)(x + √3) (x - √3).
x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).