1,6
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The intersection is (-2, 6)
When x = -2 then y = 4 which is the common point of intersection of the two equations.
If: y = 5x^2 -2x+1 and y = 6-3x-x^2 Then: 5x^2 -2x+1 = 6-3x-x^2 Transposing terms: 6x^2 +x -5 = 0 Factorizing the above: (6x-5)(x+1) = 0 meaning x = 5/6 or x = -1 By substituting the values of x into original equations points of intersection are at (-1, 8) and (5/6, 101/36)
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
x,y = 5,6 or x = 5 and y = 6