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What is the intersection point of the lines 2x plus y equals 2 and -3x-2y equals -6?
The intersection is (-2, 6)
What is the common point of these equations x plus 2y equals 6 x plus y equals 2?
When x = -2 then y = 4 which is the common point of intersection of the two equations.
What are the points of intersection of the equations y equals 5x squared -2x plus 1 and y equals 6 -3x -x squared?
If: y = 5x^2 -2x+1 and y = 6-3x-x^2 Then: 5x^2 -2x+1 = 6-3x-x^2 Transposing terms: 6x^2 +x -5 = 0 Factorizing the above: (6x-5)(x+1) = 0 meaning x = 5/6 or x = -1 By substituting the values of x into original equations points of intersection are at (-1, 8) and (5/6, 101/36)
What is the intersection point of the lines 2X plus y equals -6 and -3X-2y equals 10?
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
What is the point of intersection between points 2x-4 and x plus 1?
x,y = 5,6 or x = 5 and y = 6
What is the intersection point of the lines 2x plus y equals 2 and -3x-2y equals -6?
The intersection is (-2, 6)
Where does the line intersect x equals 5 and x-2y equals 6?
x = 5 x-2y = 6 => x = 6+2y 6+2y = 5 2y = 5-6 2y = -1 y = -1/2 and x = 5 Point of intersection: (5, -1/2)
What is the common point of these equations x plus 2y equals 6 x plus y equals 2?
When x = -2 then y = 4 which is the common point of intersection of the two equations.
What point is the intersection of the graphs of the lines 2X-Y equals 3 and X plus Y equals 3?
2X-Y=3 X+Y=3 ---------- 3X = 6 X=2 2(2)-Y=3 4-Y=3 Y=1 Point of interesection: (2,1).
What is the point of intersection when 4y -2x equals 7 meets 5y -3x equals 6?
The point of intersection is when a set value of x and y works in both equations - this is a set of simultaneous equations to solve:4y - 2x = 75y - 3x = 65×(1) - 4×(2) → (20y - 20y) + (-10x - -12x) = 35 - 24 → 2x = 11solving (3) gives x = 5.5Substituting for y in (2) gives 5y - 3 × 5.5 = 6 → 5y = 22.5 → y = 4.5Checking by substituting for y and x in (1) gives 4×4.5 - 2×5.5 = 18 - 11 = 7 as required→ the point of intersection of 4y - 2x = 7 and 5y - 3x = 6 is (5.5, 4.5)
What are the points of intersection of the equations y equals 5x squared -2x plus 1 and y equals 6 -3x -x squared?
If: y = 5x^2 -2x+1 and y = 6-3x-x^2 Then: 5x^2 -2x+1 = 6-3x-x^2 Transposing terms: 6x^2 +x -5 = 0 Factorizing the above: (6x-5)(x+1) = 0 meaning x = 5/6 or x = -1 By substituting the values of x into original equations points of intersection are at (-1, 8) and (5/6, 101/36)
What is the intersection point of the lines 2X plus y equals -6 and -3X-2y equals 10?
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
What is the common point of these equations x plusy equals 6 x plus y equals 2?
x + y = 6x + y = 2These two equations have no common point (solution).If we graph both equations, we'll find that each one is a straight line.The lines are parallel, and have no intersection point.
What is the point of intersection between points 2x-4 and x plus 1?
x,y = 5,6 or x = 5 and y = 6
Where are the points of intersection of the parabolas of y equals 5x squared -2x plus 1 and y equals 6 -3x -x squared?
If: y = 5x^2 -2x +1 and y = 6 -3x -x^2 Then: 5x^2 -2x +1 = 6 -3x -x^2 Transposing terms: 6x^2 +x -5 = 0 Factorizing the above: (6x -5)(x +1) = 0 meaning x = 5/6 or x = -1 By substitution points of intersection are at: (5/6, 101/36) and (-1, 8)
What is the answer for 1 what equals 6?
What is the answer for 1+what equals 6
What is the point of intersection of the line y equals 3x and the line y equals x plus 4?
You can work this out by solving one of the equations for either of the variables, and substituting that solution for that variable in the other equation. That will give you one either the X or Y co-ordinate for the point of intersection, and you can calculate the other one with one by plugging that back into one of the original equations: y = x + 4 y = 3x ∴ 3x = x + 4 ∴ 2x = 4 ∴ x = 2 y = 3x ∴ y = 6 So the point of intersection between the lines y = 3x and y = x + 4 is (2, 6).
