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If: y = 5x^2 -2x+1 and y = 6-3x-x^2

Then: 5x^2 -2x+1 = 6-3x-x^2

Transposing terms: 6x^2 +x -5 = 0

Factorizing the above: (6x-5)(x+1) = 0 meaning x = 5/6 or x = -1

By substituting the values of x into original equations points of intersection are at (-1, 8) and (5/6, 101/36)

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6y ago
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6y ago

They are (-1, 8) and (5/6, 101/36). The coordinates of the second point are approx (0.8333... , 2.80555...)

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Q: What are the points of intersection of the equations y equals 5x squared -2x plus 1 and y equals 6 -3x -x squared?
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