The factors are -1(2x + 1)(3x + 4)
I'm not sure this was notated correctly. As written, this is -11x plus or minus 18, which doesn't factor.
I assume you mean...,X2 + 11X + 10(X + 1)(X + 10)==============factored
x^3 - 121x
It doesn't factor evenly if it were x**2-11x+10: x**2-11x+10 = (x-1)(x-10)
The "difference of squares" has a formula. (11x + 1)(11x - 1)
(x - 1)(2x - 9)
(2x - 1)(5x + 8)
Factor out -2: -2(x squared +11x-20). This is fully factored.
x^3 - 121x
No answer in integers, nor outside the realm of imaginary numbers. Typo?
3x2 - 11x - 4 = (x-4)(3 x + 1)
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
21
x = -28 / -11^2
(11x - 2)(3x - 5)
To factor the expression (6x^2 + 12x^2 - 7x^2), first combine like terms. This gives ( (6 + 12 - 7)x^2 = 11x^2). The expression simplifies to (11x^2), which is already in its simplest factored form as (11x^2).
I'm not sure this was notated correctly. As written, this is -11x plus or minus 18, which doesn't factor.