It is an equation: 3x+11=32 and the value of x is 7
x times the sum of x and 9 x times (x times 9) x(9x) 9 times x[squared] 9x[squared]
First sum the terms with x: 9x + (-3)x = 6 x. Then sum the terms without x: -11 + (-13)x = -24. Then 6x - 24 =0 or x = 24/6 = 4
5(x^2 + y)
To find 2 times the sum of x and y, you first need to calculate the sum of x and y by adding the two variables together. Once you have the sum, you multiply it by 2 to get the final result. In mathematical terms, the expression for 2 times the sum of x and y can be written as 2(x + y).
It is an equation: 3x+11=32 and the value of x is 7
3x+11 = 32 3x = 32-11 3x = 21 The solution is: x = 7
x times the sum of x and 9 x times (x times 9) x(9x) 9 times x[squared] 9x[squared]
(11 x 5) + (11 x 6) = 11 x 11 = 121
First sum the terms with x: 9x + (-3)x = 6 x. Then sum the terms without x: -11 + (-13)x = -24. Then 6x - 24 =0 or x = 24/6 = 4
5(x^2 + y)
11(5 + 6) = (11 x 5) + (11 x 6) = 11 x 11 = 121
x(9+x)=x^2 + 9x
11 x 11 x 11 = 1,331
2 x 2 x 5 x 7 x 11 = 1540
=7(x+s)
Try a factor tree. 99 33,3 11,3,3 3 x 3 x 11 = 99