Q: X times the sum of x and 11?

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It is an equation: 3x+11=32 and the value of x is 7

x times the sum of x and 9 x times (x times 9) x(9x) 9 times x[squared] 9x[squared]

First sum the terms with x: 9x + (-3)x = 6 x. Then sum the terms without x: -11 + (-13)x = -24. Then 6x - 24 =0 or x = 24/6 = 4

5(x^2 + y)

=7(x+s)

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It is an equation: 3x+11=32 and the value of x is 7

3x+11 = 32 3x = 32-11 3x = 21 The solution is: x = 7

x times the sum of x and 9 x times (x times 9) x(9x) 9 times x[squared] 9x[squared]

(11 x 5) + (11 x 6) = 11 x 11 = 121

First sum the terms with x: 9x + (-3)x = 6 x. Then sum the terms without x: -11 + (-13)x = -24. Then 6x - 24 =0 or x = 24/6 = 4

5(x^2 + y)

11(5 + 6) = (11 x 5) + (11 x 6) = 11 x 11 = 121

x(9+x)=x^2 + 9x

11 x 11 x 11 = 1,331

2 x 2 x 5 x 7 x 11 = 1540

=7(x+s)

Try a factor tree. 99 33,3 11,3,3 3 x 3 x 11 = 99