First sum the terms with x: 9x + (-3)x = 6 x. Then sum the terms without x: -11 + (-13)x = -24. Then 6x - 24 =0 or x = 24/6 = 4
When a number is added to its additive inverse, the sum equals zero. The additive inverse of a number ( x ) is ( -x ), so when you calculate ( x + (-x) ), the result is ( 0 ). This property holds true for all real numbers.
x - 6x = 0-5x= 0x = 0/-5which equals x = 0
Simply put, No.
So we have x^2 + 3*x = 180 --> x^2 + 3*x - 180 = 0. This can factor into (x-12)(x+15)=0, So x = -15 or x = 12 satisfies it: -15 is the answer. I factored by looking for factors which sum to +3 and multiply to -180
Find two numbers that sum to -6 and which multiply to 5. The answer to that is -1 and -5 So: x2 - 6x + 5 = 0 implies (x - 1)*(x - 5) = 0 which is true if and only if x - 1 = 0 or x - 5 = 0 which is true if and only if x = 1 or x = 5
the sum equals x+10
When a number is added to its additive inverse, the sum equals zero. The additive inverse of a number ( x ) is ( -x ), so when you calculate ( x + (-x) ), the result is ( 0 ). This property holds true for all real numbers.
x=0
x - 6x = 0-5x= 0x = 0/-5which equals x = 0
Simply put, No.
It equals 0
SUM
x=0
So we have x^2 + 3*x = 180 --> x^2 + 3*x - 180 = 0. This can factor into (x-12)(x+15)=0, So x = -15 or x = 12 satisfies it: -15 is the answer. I factored by looking for factors which sum to +3 and multiply to -180
-6x
anything x 0 = 0
Find two numbers that sum to -6 and which multiply to 5. The answer to that is -1 and -5 So: x2 - 6x + 5 = 0 implies (x - 1)*(x - 5) = 0 which is true if and only if x - 1 = 0 or x - 5 = 0 which is true if and only if x = 1 or x = 5