3x + 7y = 14
Subtract 3x from each side:
7y = -3x + 14
Divide each side by 7:
y = -3/7 x + 2
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
23
x=7
-3x + 5 = 20 -3x = 15 x = -5
If: 3x+7 = -14 Then: x = -7
x = 6
If: 3x+8 = 14 Then: 3x = 14-8 So: 3x = 6 Divide both sides by 3: x = 2
balance the equation 3x-x=20-6 3x-x=2x 20-6=14 2x=14 x=7
-3x+14 = -4 -3x = -4-14 -3x = -18 x = 6
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
23
x=7
x = -8
3
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
-3x + 5 = 20 -3x = 15 x = -5
3x+5=14 3x=9 x=3