y = -4x2 - 16x - 11
you can try to factor it or use the quadratic formula:
x = (-b + (b2-4ac)1/2)/(2a)
x = (-b - (b2-4ac)1/2)/(2a)
so...
x = (16 +/- (162- (4*-4*-11))1/2)/(2*-4)
x = (16 +/- (80)1/2)/-8
in decimals, you have:
x = (16+8.944)/-8 = -3.118
x = (16-8.944)/-8 = -0.882
a = 3 and y = 0
y=9x=3it equals ......y= 3.334
The y-intercept equals 0.
y=10
Transitive property: If 8 equals x and x equals y, then 8 equals y.
y=kx^2 hence k=198/36. now y=198/36*(2)^2 y=22
Not if you want REAL solutions: y=4x^4 +2x^2 +3 t=x^2 therefore y=4t^2 +2t +3 Use discriminant: b^2-4ac=4-48=-44 this means there will be no REAL solutions (but there will be COMPLEX solutions-message me if you need this bit explained)
a = 3 and y = 0
it lies in the 2nd and 4th quadrants
y=9x=3it equals ......y= 3.334
x equals y
y=9
The y-intercept equals 0.
-17 + y,,must be equals to..-17y..
y=10
x equals -12 and y equals 1/4 of -12, so y = -3.
Transitive property: If 8 equals x and x equals y, then 8 equals y.