I,ii
It will pass through the first (when x is positive) and third quadrants (when x is negative, y will also be negative).
Quadrants I and III, numbered from I at upper right (+, +) left and moving clockwise. The line passes through the origin (0,0).
For any polynomial equation, there must be no constant term.For equations in general there is no easy way. Substitute 0 for each of the variables and if the resulting expression is 0 then the line passes through the origin.
Not enough information has been given but in general the equation of a straight line is y = mx+b whereas m is the slope and b is the y intercept.
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
depends on line slope
It passes through Quadrants II and IV. It also passes through the origin ... the point where the 'x' and 'y' axes cross. At that point, it's in all four quadrants.
I,ii
II and IV
At what point does line represented by the equation 8x + 4y = -4 intersects the y-axis, and at what point in the negative direction of x-axis.
no
no
yes
It will pass through the first (when x is positive) and third quadrants (when x is negative, y will also be negative).
The slope is always positive A negative slope will always pass through quadrant II and IV
Quadrants I and III, numbered from I at upper right (+, +) left and moving clockwise. The line passes through the origin (0,0).