x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
x2 - 10x - 6 = 2x + 1 Subtracting 2x + 1 from both sides gives: x2 - 12x - 7 = 0
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
If x=4 then 2x+7 =
X=7
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
The answer is (3.5)2 plus (4)2 equals 410.
x2+2x-63 = (x-7)(x+9) when factored
x2 - 10x - 6 = 2x + 1 Subtracting 2x + 1 from both sides gives: x2 - 12x - 7 = 0
x2 - 2x + 55 = 90x2 - 2x - 35 = 0(x+5)(x-7) = 0x = -5, 7
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).
2x = -7 - 8y
If x=4 then 2x+7 =
If: y = 2x+k and y = x2-2x-7 Then: x2-2x-7 = 2x+k And so: x2-4x-7-k = 0 Using the discriminant of b2-4ac = 0 gives k a value of -11 Using the quadratic equation formula: x2-4x+4 = 0 gives x a duel value of 2 Therefore point of contact: (2, 0)
8x-7 plus 2x equals 6 plus 5x plus 2?
if x2 + 7 = 37, then x2 = 29 and x = ±√29