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An equation with tw unknowns, x and y cannot be solved.
Two different equations containing x and y and numbers (including 0 as a number).
You have here Y = (X x 2) - 6X + 14, which equals 2X - 6X - 14 which equals
(-4X) - 14, so Y = -(4X + 14), but you cannot find the values of X and of Y.
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What is the vertex of the function y equals x2 plus 6x-5?
x = -3y = -14
X2 plus 6x plus 8 equals?
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
How do you solve x2 - 6x - 13 equals 14?
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
What is equivalent to y equals x2 - 6x plus 14?
The following equations are all equivalent to y = x2 - 6x + 14:y - 5 = (x - 3)22y = 2x2 - 12x + 28± √(y - 5) = x - 3y = [x4 - 4(3x3 + [4x]2 - 42x + 49)]1/2y - 5 = x2 - 6x + 92y - 5 = 2(x2 - 6x) + 23x = 3 ± √(y - 5)
How many roots does y equals x2 - 6x plus 9 have?
one
What is the vertex of the function y equals x2 plus 6x-5?
x = -3y = -14
X2 plus 6x plus 8 equals?
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
X2 plus 6x plus 9 equals 81?
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
How do you solve x2 - 6x - 13 equals 14?
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
What are the roots of x2 plus 6x plus 12 equals 0?
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
What is equivalent to y equals x2 - 6x plus 14?
The following equations are all equivalent to y = x2 - 6x + 14:y - 5 = (x - 3)22y = 2x2 - 12x + 28± √(y - 5) = x - 3y = [x4 - 4(3x3 + [4x]2 - 42x + 49)]1/2y - 5 = x2 - 6x + 92y - 5 = 2(x2 - 6x) + 23x = 3 ± √(y - 5)
How many roots does y equals x2 - 6x plus 9 have?
one
What is the vertex of y equals x2-6x plus 6?
(3, -21)
What is the range of y equals x2 plus 6x plus 11?
y ≥ 11
X2 plus 6x-2 equals 0?
x2 + 6x - 2 = 0 x2 + 6x + 9 = 13 (x + 3)2 = 13 x + 3 = ± √13 x = -3 ± √13
What does the equation y equals x2 - 6x plus 2 become after completing the square?
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
What is -x2 plus 6x plus 7 equals 0?
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}
