An equation with tw unknowns, x and y cannot be solved.
Two different equations containing x and y and numbers (including 0 as a number).
You have here Y = (X x 2) - 6X + 14, which equals 2X - 6X - 14 which equals
(-4X) - 14, so Y = -(4X + 14), but you cannot find the values of X and of Y.
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x = -3y = -14
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
The following equations are all equivalent to y = x2 - 6x + 14:y - 5 = (x - 3)22y = 2x2 - 12x + 28± √(y - 5) = x - 3y = [x4 - 4(3x3 + [4x]2 - 42x + 49)]1/2y - 5 = x2 - 6x + 92y - 5 = 2(x2 - 6x) + 23x = 3 ± √(y - 5)
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