The number is 44; 4 + 4 = 8.
I am less than 100 so the range is 01 - 99, but as I am divisible by 2 then I am even. As my tens digit and ones digit are the same then I am a 2 digit number so the range is now 10 - 98. The sum of my digits is 8, my tens digit and my ones digit are the same . . so the only solution is 44.
There is no number. 100 is the only one that has a hundreds digit. It's impossible.
x = hundreds digit y = tens digit z = ones digit x = z X + Z + 8 2X + 8 X = 4 = Z Y = Z -2= 4 -2 = 2 Answer: 424
63
10,234
Multiplying a 2-digit number by a 1-digit number involves multiplying the digits in the ones and tens place and then adding the products. Similarly, multiplying a 3-digit number by a 1-digit number follows the same principle, where you multiply the digits in the ones, tens, and hundreds place and then add the products. The main difference is that in the latter case, you are dealing with three sets of digits to multiply and add, whereas in the former, you only have two sets of digits.
I am less than 100 so the range is 01 - 99, but as I am divisible by 2 then I am even. As my tens digit and ones digit are the same then I am a 2 digit number so the range is now 10 - 98. The sum of my digits is 8, my tens digit and my ones digit are the same . . so the only solution is 44.
There is no number. 100 is the only one that has a hundreds digit. It's impossible.
x = hundreds digit y = tens digit z = ones digit x = z X + Z + 8 2X + 8 X = 4 = Z Y = Z -2= 4 -2 = 2 Answer: 424
63
19
3333
98
10,234
44? ? ?
No.
The greatest 3 digit number is 999, and all three digits are the same.