The same as rolling an odd number...
1:2 or 50% chance.
The probability is 1, if the dice are rolled often enough.
To find the probability of getting an odd number at least once when a die is tossed thrice, we can use the complementary approach. The probability of not getting an odd number (i.e., getting an even number) in a single toss is ( \frac{3}{6} = \frac{1}{2} ). Therefore, the probability of getting an even number in all three tosses is ( \left(\frac{1}{2}\right)^3 = \frac{1}{8} ). Thus, the probability of getting an odd number at least once is ( 1 - \frac{1}{8} = \frac{7}{8} ).
zero as you only have 3 dice, with the number 6 on them only once on each dice. so if you are lucky you can only throw 6 3 times using 3 dice.
Total number of possible rolls with 2 dice = 36.Total number of rolls that are doubles = 6.Probability of rolling doubles= 6/36 = 1/6 = (16 and 2/3) percent .
The probability of getting a sum of 2 at least once is 0.8155
The probability is .5 since half the numbers are even and half are odd.
The probability is 1, if the dice are rolled often enough.
The probability of rolling a specific number on a fair six-sided dice is 1/6, as there are 6 equally likely outcomes. When rolling the dice 300 times, the probability of rolling that specific number on each roll remains 1/6, assuming the dice is fair and each roll is independent. Therefore, the probability of rolling that specific number at least once in 300 rolls can be calculated using the complement rule, which is 1 minus the probability of not rolling the specific number in all 300 rolls.
That depends on what kind of dice you are rolling and how many of them you roll. If you roll two 6-sided dice once, the probability of getting the number 100 is exactly zero. You cannot get a 100 on one roll of two 6-sided dice. Other dice and different numbers of them may yield different probabilities.
If two dice are rolled once, the probability is 30/36 = 5/6
there is six sides on a dice and three of them is odd3/6=1/2=50%it's a 50% chance to roll an odd number
4/6 or 2/3
To find the probability of getting an odd number at least once when a die is tossed thrice, we can use the complementary approach. The probability of not getting an odd number (i.e., getting an even number) in a single toss is ( \frac{3}{6} = \frac{1}{2} ). Therefore, the probability of getting an even number in all three tosses is ( \left(\frac{1}{2}\right)^3 = \frac{1}{8} ). Thus, the probability of getting an odd number at least once is ( 1 - \frac{1}{8} = \frac{7}{8} ).
zero as you only have 3 dice, with the number 6 on them only once on each dice. so if you are lucky you can only throw 6 3 times using 3 dice.
The probability of rolling 7 once with two dice is 1 in 6, o 0.1667. The probability, then, of doing that twice in a row is 1 in 36, or 0.02778.
Total number of possible rolls with 2 dice = 36.Total number of rolls that are doubles = 6.Probability of rolling doubles= 6/36 = 1/6 = (16 and 2/3) percent .
The probability of getting a sum of 2 at least once is 0.8155