yes. they are not congruent
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No, the diagonals of a parallelogram are not normally congruent unless the parallelogram is a rectangle.
square and rectangle
False
This cannot be proven, because it is not generally true. If the diagonals of a quadrilateral bisect each other, then it is a parallelogram. And conversely, the diagonals of any parallelogram bisect each other. However not every parallelogram is a rhombus.However, if the diagonals are perpendicular bisectors, then we have a rhombus.Consider quadrilateral ABCD, with diagonals intersecting at X, whereAC and BD are perpendicular;AX=XC;BX=XD.Then angles AXB, BXC, CXD, DXA are all right angles and are congruent.By the ASA theorem, triangles AXB, BXC, CXD and DXA are all congruent.This means that AB=BC=CD=DA.Since the sides of the quadrilateral ABCD are congruent, it is a rhombus.
No, the properties of a paralleogram are as follows:two parallel sidesbisecting diagonalsequal opposite anglesand it does not need to have all equal sides it just needs to have OPPOSITE equal sidesIf the diagonals were equal, the figure would have to be a square, rectangle, or rhombus.No. In fact they are equal only in exceptional circumstances.