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305 can only be [exactly] divided by 5 and not 2, 3, 6, 9 nor 10.

Divisibility tests:

  • 2: No
Number must be even (last digit divisible by 2).

Last digit is 5 which is not even, so the whole number (305) not divisible by 2.

  • 3: No
Add up the digits of the number; if this sum is divisible by 3, then the original number is divisible by 3:

3 + 0 + 5 = 8 which is not divisible by 3, so the original number (305) is not divisible by 3.

  • 5: Yes
Last digit is 0 or 5. Last digit is 5, so 305 is divisible by 5.
  • 6: No
6 = 2 x 3, so number must pass both tests for divisibility of 2 and 3; 305 fails tests for (both) 2 and 3 (above), so is not divisible by 6.
  • 9: No
Add up the digits of the number; if this sum is divisible by 9, then the original number is divisible by 9:

3 + 0 + 5 = 8 which is not divisible by 9, so the original number (305) is not divisible by 9.

  • 10: No
The last digit of the number must be 0. Last digit is 5, so 305 is not divisible by 10.
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โˆ™ 2011-09-30 08:40:33
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Algebra

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Q: Can you divide 2 3 5 6 9 10 into 305?
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