They bisect each other at an angle of 90 degrees
Yes. The diagonals of any parallelogram bisect each other. A rectangle is a special case of a parallelogram.
Yes
Yes the diagonals of a parallelogram have the same midpoint since they bisect each other.
This cannot be proven, because it is not generally true. If the diagonals of a quadrilateral bisect each other, then it is a parallelogram. And conversely, the diagonals of any parallelogram bisect each other. However not every parallelogram is a rhombus.However, if the diagonals are perpendicular bisectors, then we have a rhombus.Consider quadrilateral ABCD, with diagonals intersecting at X, whereAC and BD are perpendicular;AX=XC;BX=XD.Then angles AXB, BXC, CXD, DXA are all right angles and are congruent.By the ASA theorem, triangles AXB, BXC, CXD and DXA are all congruent.This means that AB=BC=CD=DA.Since the sides of the quadrilateral ABCD are congruent, it is a rhombus.
The diagonals of a square bisect each other at 90 degrees
The diagonals of a square (which always bisect each other) are the same length.
A square has 4 interior right angles and its diagonals bisect each other at 90 degrees.
Square
always
Yes
Yes
Square, rhombus and a kite have diagonals that bisect each other at 90 degrees
A parallelogram a rectangle a square and a rhombus
Yes they do, in a square.
Square, Rhombus
A square and a rhombus