Yes they do, in a square.
A rectangle. Note: a square is a regular rectangle where all sides are equal; in this case not only are the diagonals equal and bisect each other, they also bisect perpendicularly, that is at 90o to each other.
Not necessarily - the diagonals of a rhombus bisect each other (they are perpendicular bisectors of each other), but are not equal.
An isosceles trapezoid, or any trapezoid, does not have diagonals that bisect each other.
No.
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
squares
A rectangle. Note: a square is a regular rectangle where all sides are equal; in this case not only are the diagonals equal and bisect each other, they also bisect perpendicularly, that is at 90o to each other.
Yes, the diagonals of a parallelogram bisect each other.
The diagonals of a square (which always bisect each other) are the same length.
The diagonals of a square bisect each other at 90 degrees
Yes the diagonals of a kite bisect each other at 90 degrees.
Yes. Because the diagonals are perpendicular to each other and intersect at their midpoints, they bisect each other.
Not necessarily - the diagonals of a rhombus bisect each other (they are perpendicular bisectors of each other), but are not equal.
An isosceles trapezoid, or any trapezoid, does not have diagonals that bisect each other.
No, the diagonals of a trapezoid do not necessarily bisect each other. Only in an isosceles trapezoid, where the two non-parallel sides are congruent, will the diagonals bisect each other. In a general trapezoid, the diagonals do not bisect each other.
squares
A circle!! * * * * * Wrong: the diagonals of a circle DO bisect each other. A triangle is a possible answer.