As a product of its prime factors: 2*2*2*7*127 = 7112
They are: 2, 3 and 5
150 = 2 x 3 x 5 x 5
The prime factors of 600 are 2, 2, 2, 3, 5, and 5. The prime factors of 1350 are 2, 3, 3, 3, 5, and 5. The prime factors they have in common are 2, 3, 5, and 5, so the greatest common factor is 2 x 3 x 5 x 5 = 150.
Those can be found at primes.utm.edu/lists/small/10000.txt
150 = 2 x 3 x 52
The prime factorization of 150 is 2 * 3 * 5^2. The distinct prime factors are 2, 3, and 5. To find the product of these distinct prime factors, you simply multiply them together: 2 * 3 * 5 = 30. Therefore, the product of the distinct prime factors of 150 is 30.
the prime factors of 150 is 2,3,5,5 Product of this factors are 2 x 3 x 5 x 5 = 150
The product of the prime factors of 150 is 150 (2 x 3 x 5 x 5 = 150).
As a product of its prime factors: 2*3*5*5 = 150 or as 2*3*52 = 150
As a product of its prime factors: 2*3*5*5 = 150 or as 2*3*52 = 150
The prime factorization of 150 is 2x3x5x5.
As a product of its prime factors it is: 2*3*5*5 = 150 or as 2*3*52 = 150
the prime factorization of 150= 2x3x52 If we use all the factors, the answer would of course be 150 if we use just 2,3 and a single 5, not 52 , then the answer is 30
As a product of its prime factors: 2*3*5*5 = 150 Or: 3+13+37+97 = 150
150 = 2 x 3 x 5 x 5
2 x 3 x 5 x 5 = 150