x(y-10)+6(y-10)
^^^that's the first step, then:
the x and 6 pair together, and one of the (y-10) leaves the expression so it becomes:
(x+6)(y-10)
this is referred to as Factoring by Grouping
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
The LCM is 455x.
x3 + 2x2 - 35x = x(x2 + 2x - 35) = x(x + 7)(x - 5)
The correct answer is one of: A: (7x + 5)*(7x + 6) = 49x2 + 77x + 30 B: (7x + 5)*7x + 6 = 49x2 + 35x + 6 C: 7x + 5*7x + 6 = 42x + 6 Since there are no brackets in the question, the correct answer is C but I suspect there should be brackets but this site does not allow them.
35
(5x - 7)(7x + 5)
25x + 35x + 9 is 60x + 9, which factors to 3(20x + 3)
7(5x + 4y)
x2-35x+300 = 0 (x-15)(x-20) = 0 x = 15 or x = 20
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
35x + 115 = 360 35x = 360-115 35x = 245 x = 245/35 x = 7
Oh, what a happy little math problem we have here! To factor 35x + 63y, we can first look for the greatest common factor of the coefficients, which is 7. Then we can factor out the 7 to get 7(5x + 9y). And just like that, we've created a beautiful and simplified expression!
42x+35x-35x=42x it's leave 85 so it's change into a negative 42x-85 is the answer
35x + 10
x3 + 2x2 - 35x = x(x + 7)(x - 5)
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
5x2