x(y-10)+6(y-10)
^^^that's the first step, then:
the x and 6 pair together, and one of the (y-10) leaves the expression so it becomes:
(x+6)(y-10)
this is referred to as Factoring by Grouping
5x2 - 20y2 = 5(x2 - 4y2) = 5[(x)2 - (2y)2] = 5(x - 2y)(x + 2y)
5(x^2 - 4xy + 2y^2)
5(x - 2y)(x + 2y)
(5x - y)(5x - y) or (5x - y)2
(4y + 1)(3y + 2)
5(7x^2y + 6x^2 + 8)
5x(2x - 3y)
5x ^ 2 - 20y ^ 2
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
The LCM is 455x.
x3 + 2x2 - 35x = x(x2 + 2x - 35) = x(x + 7)(x - 5)
The correct answer is one of: A: (7x + 5)*(7x + 6) = 49x2 + 77x + 30 B: (7x + 5)*7x + 6 = 49x2 + 35x + 6 C: 7x + 5*7x + 6 = 42x + 6 Since there are no brackets in the question, the correct answer is C but I suspect there should be brackets but this site does not allow them.
35
(5x - 7)(7x + 5)
25x + 35x + 9 is 60x + 9, which factors to 3(20x + 3)
7(5x + 9y)
7(5x + 4y)
x2-35x+300 = 0 (x-15)(x-20) = 0 x = 15 or x = 20
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
35x + 115 = 360 35x = 360-115 35x = 245 x = 245/35 x = 7
42x+35x-35x=42x it's leave 85 so it's change into a negative 42x-85 is the answer
35x + 10
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
x3 + 2x2 - 35x = x(x + 7)(x - 5)