10x**2-31x+14
Multiply first and last terms:
10*14=140
Find 2 Factors of 140 whose sum is -31
140=2*2*5*7
Factors:
4*35
10*14
7*20
2*70
5*28
None of these add up to -31
HOWEVER: I will continue this as if it was minus 14 instead of plus (so that I can show you how to do such a question)
Factor
4+-35=-31
rewrite:
10x**2-35x+4x-14
Factor sets of terms
10x**2-35x+4x-14=5x(2x-7)+2(2x-7)
Factor
5x(2x-7)+2(2x-7)=(5x+2)(2x-7)
5xx+14x-48
Steps
1. Multiply first and third terms:
5*-48=-240
2. Factor -240, find two factors that add up to the second term:
-240=2*2*2*2*3*5
-240=-2*120, 2*-120
-240=-3*80, 3*-80
-240=-5*48, 5*-48
-240=-4*60, 4*-60
-240=-6*40, 6*-40
-240=-15*16, 15*-16
-240=-8*30, 8*-30
-240=-12*20, 12*-20
-240=-24*10, 24*-10
3. Rewrite the polynomial:
5xx+14x-48
5xx+24x-10x-48
4. Factor pairs of terms (ie. first and second terms, third and fourth terms):
5xx+24x-10x-48
x(5x+24)-2(5x+24)
5. Combine like terms:
x(5x+24)-2(5x+24)
(x-2)(5x+24)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 3 plus or minus -1 times the square root of 23.
x = -1.7958315233127191
x = 7.7958315233127191
6y2+17y-14 = (2x+7)(3x-2) when factored
14 x 7 = 28 + 70 = 98
It is 7*(1 + 2).
Common Factors: 14,7,2,1 Greatest Common Factor: 14
The greatest common factor (GCF) is: 14
hey
(x - 1)(x - 14)
2(y + 7)
(x+7)(x+2)
-9
-(x - 7)(x + 2)
(x-2)(2x+7)
4s^2 + s - 14 = (4s - 7)(s + 2)
-2x+12x+28=10x+28 ;Combining like factors2(5x+14) ; Factor out a two from both of them
3z2 + 45z + 42 = 3(z2 + 15z + 14) = 3(z + 1)(z + 14).
(2x + 7)(x - 2)
(w + 7)(w - 2)