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Out of the factor pairs of 1728, only 144 and 12 have a square/square root relationship. 12 has to be the cube root of 1728.

(1728,1)(864,2)(576,3)(432,4)(288,6)(216,8)(192,9)(144,12)(108,16)(96,18)(72,24)(64,27)(54,32)(48,36)

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Q: Find the cuberoot of 1728 by factor method?
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