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The factors of 3300 are: 1, 2, 3, 4, 5, 6, 10, 11, 12, 15, 20, 22, 25, 30, 33, 44, 50, 55, 60, 66, 75, 100, 110, 132, 150, 165, 220, 275, 300, 330, 550, 660, 825, 1100, 1650, and 3300.

The prime factors of 3300 are: 2, 3, 5, and 11.

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Keep dividing until you can't any more.

2 x 3 x 5 = 30

As a product of its prime factors: 2*2*3*5*5 = 300 or as 22*3*52 = 300

330 = 2 × 3 × 5 × 11

330

10, 33

2, 5, 3, 11

336 = 24 × 3 × 7

1,300 = 2*2*5*5*13

Q: Find the prime factorization of 1300?

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As a product of its prime factors: 2*2*5*5*13 = 1300

It is: 22*52*13 =1300

1 + 2 + 4 + 5 + 10 + 13 + 20 + 25 + 26 + 50 + 52 + 65 + 100 + 130 + 260 + 325 + 650 + 1300 = 3,038

22 x 52 x 13

1300 = 2 * 2 * 5 * 5 * 13 = 22 * 52 * 13

22 x 52 x 13 = 1300

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