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You use the distributed property to find out if you have the same answer as you started out with.

ex. 81x2+12t

...../....\.....

....9.....9...2....6

..../\..../\.......|......

...3..3.3.3xx.2....2.3t

3(27x2+2t)

3*27x2 3*2t

81x2+12t

OR..

9x2-1 = (3x+1)(3x-1) but to check it we multiple 3x and 3x to get 9x2 and theh 3x by -1 to get -3x then 1 by 3x to get positive 3x and then 1 and -1 to get a -1 so we end up with it looking like this 9x2-3x+3x-1 now since -3x+3x=0 we are left with the 9x2-1

the 9 needs to be multplied twice by the same number to get the number needed. so we have 9x2 needs to be broken up to 3x and 3x so that wen its multiplied we get 9x2 and for the -1.. we need to multiply the -1 by a positive 1 so that the can cancel out each other but we would get a -3x and a positive 3x that will cancel out each other to give us our final answer!

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