Using trigonometery if you know the length of its shadow and angle of elevation
it can grow upto 400ft in height
The average height of a Joshua Tree is 17in.
the average height of an oak tree is 60ft the average height of an oak tree is 60ft
o(logN)
7 Meters
tree x width x height divided by 3
we can find the balance factor of highty balance tree with height of left subtree- height of right sub tree
Check this out! http://stackoverflow.com/questions/575772/the-best-way-to-calculate-the-height-in-a-binary-search-tree-balancing-an-avl
Tan60= 25/Height. Height = 25/Tan60 = 14.43
it can grow upto 400ft in height
To find the height of the tree, we can set up a proportion using the similar triangles formed by the tree and its shadow, and the person and their shadow. The ratio of the height of the tree to its shadow is the same as the ratio of the height of the person to their shadow. This gives us (height of tree)/(9 ft) = (6 ft)/(4 ft). Solving for the height of the tree, we get height of tree = (9 ft * 6 ft) / 4 ft = 13.5 ft.
All i can find is that the The tree, usually a Norway Spruce (a pine i think) is about 75 to 90 feet (23 to 27 m) tall. Every year they erect a different tree i think, so the height varies.Cant find width :P
Formula for working out height of a tree is (distance from eye to base of tree/distance from eye to base of stick) x length of stick = tree height.(distance from eye to base of tree/distance from eye to base of stick) x length of stick = tree height is the formula for working out height of a tree.
The height of a complete binary tree is in terms of log(n) where n is the number of nodes in the tree. The height of a complete binary tree is the maximum number of edges from the root to a leaf, and in a complete binary tree, the number of leaf nodes is equal to the number of internal nodes plus 1. Since the number of leaf nodes in a complete binary tree is equal to 2^h where h is the height of the tree, we can use log2 to find the height of a complete binary tree in terms of the number of nodes.
The average height of a Joshua Tree is 17in.
the height is (20.5)
A simple angle of elevation problem...You want to find out the height of a tree. You measure the distance from you to the base and find that it is 100 feet. You measure the angle of elevation of the top and find that it is 30 degrees. You are six feet tall. How tall is the tree?Answer: The tree is 64 feet tall. Its height is tangent 30 times 100 + 6.