To find the height of the tree, we can set up a proportion using the similar triangles formed by the tree and its shadow, and the person and their shadow. The ratio of the height of the tree to its shadow is the same as the ratio of the height of the person to their shadow. This gives us (height of tree)/(9 ft) = (6 ft)/(4 ft). Solving for the height of the tree, we get height of tree = (9 ft * 6 ft) / 4 ft = 13.5 ft.
It is 90 feet in height
4 feet24/16 = 6/x24x = 96x = 4
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
That depends on the height of the yardstick whose height has not been given.
Let x be the height of the boy and seeing that they both have the same tangent ratio so it must follow that: x/3 = 11/19 Multiply both sides by 3 and then divide the product by 19: x = 1.736842105 Therefore height of boy = 1.7 meters to the nearest tenth.
3 yards in height
NO.
Designate the unknown shadow length by s. Shadows cast at the same time and place are proportional to the height of the object casing the shadow. Therefore: 4/6 = s/21, or s = [4(21)]/6 = 14 feet.
It works out as 30 feet in height
The ratio of the young man's height to his shadow is 150:200 or 3:4 The ratio for the father is the same. His shadow is 240 cm so his actual height is 240*3/4 = 180 cm
The ratio of the shadow cast to the height of an object will be the same at the same time of day. For the fence post, the height of the post is 2.5 times the length of the shadow ( 5 ft / 2 ft = 2.5 ) The tree has a 10 foot shadow, so using the same ratio for the fence post: 10 ft * 2.5 = 25 feet. The tree is 25 feet tall
The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
You can use shadows to measure the heights of trees, or buildings, as long as you can make two separate measurements at exactly the same time of day. While one person or group measures the length of the shadow of the tree or other object, another person or group carefully measures the length of the shadow cast by a smaller object, such as a person, sign, or pole.The ratio of the length of the shadow to the height of the object will be the same for almost every object casting a shadow at that particular moment of the day. So divide the known or measured height of a person by the length of his shadow to find this ratio, then multiply the other shadow length by this amount, to give a good estimate of the height of the taller object.Example:A tree's shadow at 5 PM is found to stretch 80 feet from the base of the tree.A boy is known to be 5 feet tall, his shadow at 5 PM is 10 feet long.(So the shadow length of other objects, measured at 5 PM, will all be twice their height.)5 ft/ 10 ft = 0.5 and 0.5 x 80 = 40 tells us the tree itself is about 40 feet tall.
If the shadow of a 6-ft person is 4-ft long, then in this place at this moment, all shadowsare 2/3 the length of the vertical object that casts them.The 9-ft shadow therefore 2/3 the height of the tree. The height is (9)/(2/3) = (9 x 3/2) = 13.5-ft.-----------------------------------------(9/4)*6=13.5 ft.
It's not possible to give you an answer without knowing the height of your shadow, because the height of a shadow depends on the position of the light (the lower the longer the shadow is). But if the shadow is exactly the same height as you, it would be the same inches in height as you are. To calculate that, just multiply 5 ft x 12, which = 60 inches, then add the other 3 inches to it. That would give you a total of 63 inches.
Both. At sunrise and sunset on a sunny day, your shadow will be very long. As the sun rises and approaches it's zenith at noon, your shadow becomes progessively shorter, then lengthens again throughout the afternoon.
The height of the tree is in direct proportion to the pole and its shadow