We have the algebraic expression: 12x2 - 18x - 21
First multiply coefficient of x2 with -21. The result is -21 x 12 = -252.
Now, break down coefficient of x into two numbers such that their product is -252.
-18 can't be broken into two numbers such that their product is -252.
So, 12x2 - 18x - 21 can't be factorized.
Another Answer:-
It appears that the above quadratic expression can be factored because its discriminant is greater than zero.
12x2-18x-21
Divide all terms by 3:
4x2-6x-7 = (4x+3.08276253)(x-2.2706906326) when factored correct to 8 and 10 decimal places respectively
x2 + 18x - 50 does not have rational factors.
It is: 6x
6x(3x2 - x + 4)
No 9xx-18x+36 9(xx-2x+4) xx-2x+4 (doesn't factor evenly)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (8 plus or minus the square root of 10) divided by 3 x = 3.720759220056127 x = 1.6125741132772067
12x2 - 28x - 15= 12x2 - 18x - 10x - 15= 6x(2x - 3) - 5(2x - 3)= (6x - 5)(2x - 3)
12x2-8x
12x2-x-35 = (4x-7)(3x+5)
x2 + 18x - 50 does not have rational factors.
While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
12x2-23x+10 = (3x-2)(4x-5) when factored
3x(4x - 3)
4x3+12x2+3x+9
Take out the common factor, which in this case is 4x2. Divide each of the terms by this common factor. 12x2 - 4x3 = 4x2(3+x)
4x2(4x3 + 3)
5x2-18x+9 = (5x-3)(x-3)
7Improved Answer:8x2-18x+9 = (4x-3)(2x-3)