(x+7)(x+2)
(x - 14)(x - 2)
Two numbers that multiply to give you +33 and add to give you 14 are 11 and 3. (x+11)(x+3)
That factors to (x - 14)(x - 2)
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
(x+7)(x+2)
-(x - 7)(x + 2)
(2x + 7)(x - 2)
(w + 7)(w - 2)
(x - 14)(x - 2)
3z2 + 45z + 42 = 3(z2 + 15z + 14) = 3(z + 1)(z + 14).
x2+15x+14 = (x+1)(x+14)
Two numbers that multiply to give you +33 and add to give you 14 are 11 and 3. (x+11)(x+3)
I would do this. Multiply through by -1 -1 ( -X^2 +12X +28 ) = X^2 -12X -28 (X+2)(X-14)
That factors to (x - 14)(x - 2)
(x + 2)(x - 7)
30x2-23x-14 = (6x-7)(5x+2) when factored with the help of the quadratic equation formula