How do you factor completely 3x4 13x3 11x2-5x-6?

Answer 1

You will find it too difficult to factor this expression.

If you wish to solve for the roots of this quadratic you first need to know what the expression is equal to (so you can write it in the form of ax2 + bx + c = 0) and then you should use the quadratic formula instead.

x = (-b + or - (b2 - 4ac)1/2) / 2a

============================

The factors are close to (x - 3.45743) and (x - 1.54257), and those are rounded,

so you can see why it would be difficult to try and factor the expression.

Answer 2

I will assume that where there is no mathematical operator (plus or minus), you mean to say "plus." So, the new question is this: factor completely: 3x^4 + 13x^3 + 11x^2 - 5x - 6. I know the equation doesn't say "=0" but for now, it will make things easier. 3x^4 + 13x^3 + 11x^2 - 5x - 6 = 0. All the possible zeroes of this equation can be found by dividing the integer factors of the last piece of the equation (6) by the integer factors of the leading coefficient (3). Now, we have these: (±1, ±2, ±3, ±6)/(±1, ±3). This yields these: ±1, ±1/3, ±2, ±2/3, ±3, ±1, ±6, and ±2. We see a couple of these quotients multiple times, so we can keep just one of each, in ascending order: ±1/3, ±2/3, ±1, ±2, ±3, and ±6. Now we plug each one into the original equation. I did these on my own, so I'm not going to write out each possible answer. However, I will lead you through the first part of it. The best way to approach this problem is to use synthetic division, but I cannot do that on this computer. So, we will do it the long way. Let's try "x=-1." 3(-1)^4 + 13(-1)^3 + 11(-1)^2 - 5(-1) - 6 = 0. Simplify: 3(1) + 13(-1) + 11(1) - 5(-1) - 6 = 0. Simplify again: 3 + (-13) + 11 - (-5) - 6 = 0. -10 + 16 - 6 = 0. Final simplification: 0=0. Yes. Continue doing this on your own, and you WILL find every solution. Once you have the x values that satisfy the equation, you have to remember that when you asked the question on this website, there was no "=." So, what you have to do is this: we know that x=-1 was a solution, right? So, by adding 1 to both sides of the equation, we obtain x+1=0. Now, divide the original expression by "x+1" to obtain the new equation. Of course, this could mostly be avoided by synthetic division. If you do not know what I am talking about, I am deeply sorry, but I have done what I could!

Answer 3

If the missing operational signs are pluses, the answer is (3x - 2)(x + 8)(x - 1)

If the missing operational signs are minuses, the answer is (3x + 2)(x - 8)(x + 1)

Answer 4

(3x2 + 4)(x - 5)

Answer 5

19x^3-38x^2=

19x^2(x-2)