If you have the equation y=3x2+6x then you can factor it down smaller like so:
y=3x(x+2)
This is possible because there is an 'x' in both parts of the equation. You can also do it backwards, because 3x*x=3x2 and 3x*2=6x.
If you are talking about a regular problem, such as 3+4(3-7) then you'd do the stuff in parentheses first. Remember the order: PEMDAS. Parentheses, Exponents, Multiply, Divide, Add, Subtract.
There are three ways to factor with different variables.
- using the distributive property
-using the additive inverse property
-factoring by grouping
Grouping
Most people believe that factoring by grouping is the easiest
factor 4ab+8b+3a+6
= (4ab+8b)+(3a+6) group terms together with common factors
=4b(a+2) + 3(a+2) factor GCF from each grouping
= (a+2) (4b+3) use distributive property
Distributive
factor 12a2+6
First, find GCF of 12a and 16a by factoring each number
12a= 2*2*3*a*a
16a= 2*2*2*2*a
GCF= 2*2*a or 4a (like factored terms)
Now, write each term as the product of the GCF and its remainning factors. Then use the Distributive property to factor out the GCF
12a2+16a= 4a(3*a) + 4a(2*2)
= 4a(3a) + 4a(4)
= 4a(3a+4)
Just like any other quadratic/polynomial. Are there any common factors? Use GCF.
Do all the variables follow rules for a quadratic? Then consider a dummy variable to replace them. At the end of the problem you must do reverse substitution.
Ex: 5x2y2z2 + 15xyz +10 <-- GCF is 5
= 5(x2y2z2 + 3xyz +2) <--notice that x2y2z2 + (xyz)2 and sub. A = xyz so A2 = x2y2z2
= 5(A2 + 3A + 2) = 5(A+1)(A+2) <-- now must reverse substitute xyz = A
= 5(xyz +1)(xyz+2) <-- this is your answer
Use the quadratic formula to find the roots in the complex field, and use the result to factorise the trinomial.
It does not change its value whatever the value of the variables, under a given set of conditions.
No, 3 is a factor of 9.
Choose the lowest of the exponents. The GCF of x3 and x5 is x3
Since 3 is a factor of 27, it is automatically the GCF of 3 and 27
Since 3 is a factor of 42, it is automatically the GCF.
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dependent variable; this is the factor in a experiment that when manipulated by independent variables it changes. it is also known as a controlled variable independent variables or manipulated variable; the factor in a experiment that is deliberately manipulated responding variable; the factor you have to measure to get the results or you will not know the value of the variable
1. Quadratics should always contain a set of numbers inconjuction with letters (x usually). 2. Quadratics are always in the form ax2 + bx + c. Where a,b and c are constants and x is a variable. 'a' must always equal '0'. 3. The total equation must never equal '0'. 4. To solve quadratics, you DO NOT factorise. 5. To solve quadratics, use the formula x=a, therefore, b=c. 6. The word 'quadratics' literally means four. This in term means that there are four ways you can solve for the answer of the equation.
Many real life physics problems are parabolic in nature. Parabolas can be shown as a quadratic equation. If you have two variables then usually you can use the equation to find the best solution to a problem. Also, it is a beginning in the world of mathematical optimization. Some equations use more than two variables and require the technique used to solve quadratics to solve them. I just ran an optimization of 128 variables. To understand the parameters I needed to set I had to understand quadratics.
x2=100
independent variables :):):):):):):):):):):):)
Quadratics that can be written in the form y = a*(x - r)2
Temperature and pH are two; the concentration of other reactants or chemicals may be a third factor.
The controlled variables.
they're not
the coefficient
Assignment Discovery - 1992 Lines and Quadratics was released on: USA: 5 October 2006