That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (8 plus or minus 4i) divided by 5x = 1.6 + 0.8ix = 1.6 - 0.8iwhere i is the square root of negative one.
(x - 5)(x - 3)
X(5-8)
Take out the common factor, 3: 3x + 6 = 3(x + 2).
4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2
x2 + 13x + 40 = x2 + 5x + 8x + 40 = x(x + 5) + 8(x + 5) = (x + 8)(x + 5)
(5x - 7)(x + 3)
5x+8y = 40 8y = -5x+40 y = -5/8x+5 in slope intercept form
x2 + 3x - 40 = x2 + 8x - 5x - 40 = x(x + 8) - 5(x + 8) = (x - 5)(x + 8)
5x+8x+3x-2x = 14x
8x = 5x+24 8x-5x = 24 3x = 24 x = 8
If that's 15x2, the answer is (3x + 4)(5x - 4)
5x+49 = 8x+13 49-13 = 8x-5x 36 = 3x x = 12
8x-4 = -7+5x 8x-5x = -7+4 3x = -3 x = -1
8x-7 plus 2x equals 6 plus 5x plus 2?
5x+1+x-2 = 8x+6 5x+x-8x = 6+2-1 -2x = 7 x = -3.5
7+8x-5 = 8x+7-5x Subtract 7 from both sides: 8x-5 = 8x-5x Subtract 8x from both sides: -5 = -5x Divide both sides by -5: x = 1 So the equation implies x = 1