I don't think you can factor it integer wise. Yeah, it's impossible. Plugging it into the quadratic formula yields you a pair of imaginary roots.
Actually, it's just (x - root1)(x - root2). But I imagine you wanted integer roots, or at least rational roots.
x2 - x + 30 does not have any factors. If on the other hand you wanted to factor out: x2 - x - 30 Then it can be done as follows: = x2 - 6x + 5x - 30 = x(x - 6) + 5(x - 6) = (x + 5)(x - 6)
(x + 4)(x + 8)
(x + 2)(x - 1)
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
(x + 5y)(x - 3y)
x2 + 1x - 30 = (x + 6) (x - 5)
(x + 10)(x + 3)
(x + 10)(x - 3)
-28
32
-28
x^2 - x + 30 doesn't have rational factors. If that was - 30, it would factor to (x - 6)(x + 5)
(x - 10)(x - 3)
32
32
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
x2 - x + 30 does not have any factors. If on the other hand you wanted to factor out: x2 - x - 30 Then it can be done as follows: = x2 - 6x + 5x - 30 = x(x - 6) + 5(x - 6) = (x + 5)(x - 6)