(x + 10)(x + 3)
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vbh
x2 - 13x + 30 = (x - 3)(x - 10). In case you are provided with a list that you forgot to include with your question, then any of the following is a possible factor: x - 3; x - 10; 3 - x; or 10 - x.
32
-2(2x^4 - 13x^3 + 15)
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}