vbh
x2 - 13x + 30 = (x - 3)(x - 10). In case you are provided with a list that you forgot to include with your question, then any of the following is a possible factor: x - 3; x - 10; 3 - x; or 10 - x.
32
-2(2x^4 - 13x^3 + 15)
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
vbh
(x - 10)(x - 3)
X^2 - 13X + 30 = 0 (X-3)(X-10) easy inspection problem
x2 - 13x + 30 = (x - 3)(x - 10). In case you are provided with a list that you forgot to include with your question, then any of the following is a possible factor: x - 3; x - 10; 3 - x; or 10 - x.
32
-2(2x^4 - 13x^3 + 15)
You would factor out -1 (a) from a trinomial in an equation such as -a^2 +30a - 2a + 60 after the middle term has been separated. The final answer of this trinomial would then be (a-30) (a-30).
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
x^2 + 13x + 30 = 0 x^2 + 10x + 3x + 30 = 0 x(x + 10) + 3(x + 10) = 0 (x + 3)(x + 10) = 0 x = -3 or x = -10
Assuming you mean n2 + 11n + 30, the factors are (n + 6)(n + 5).
13(x + 50) = 30 13x + 650 = 30 subtract 650 to both sides; 13x = -620 divide by 13 to both sides; x = -620/13
There's a factor pair of 30 that adds up to 11. (x + 5)(x + 6)