The least common multiple (LCM) of two monomials is the smallest monomial that is a multiple of both monomials. To find the LCM of 26ab^2 and 28ac^3, we need to identify the highest power of each variable that appears in either monomial. The LCM will then be the product of these highest powers, along with any remaining unique factors. In this case, the LCM of 26ab^2 and 28ac^3 is 364a^1b^2c^3.
You need at least two numbers to find an LCM.
The prime factorization of 4 is 2 x 2. It is not possible to find the LCM of a single number.
LCM of 8, 12, 18 = 72Prime factorization of:8 = 2 * 2 * 212=2 * 2......* 318=2 ..........* 3 * 3=============LCM=2*2 * 2 * 3 *3 = 72
Step 1 Find the prime factors of each number 36 = 2×2×3×3 = 2²×3² 72 = 2³×3² 108 = 2²×3³ Step 2 Find LCM L - Highest (Find the number with the highest exponent) C - Common (Find the common number EG. 2 and 3) M - Missing ( Take what ever is missing that is not common) LCM : 2³×3³ = 216 Your LCM is 216
72(d^3)(e^2)72 is the LCM of 24 and 36.d^3 is the LCM of d and d^3.e^2 is the LCM of e^2 and e.
LCM[(13b3)3, 7b2] = LCM[2197b9, 7b2] = 2197*7*b9 = 15379*b9
The GCF is 7y^2.
You need at least two numbers to find an LCM.
Since 4 is a multiple of 2, it is automatically the LCM.
You can't find the LCM of a single number. The LCM of 1, 2, 3 and 14 is 42.
This is similar to the often-used method to find the LCM of 2 numbers: you have to factor each monomial, and eliminate duplicate factors (factors that appear in both terms). An example might make this clearer. LCM of x2 + 5x, and x2 + 6x + 1 Factoring each: x(x+5), and (x+1)(x+5) Multiply all the factors, but use the common factor (x+5) only once: x(x+5)(x+1)
Two or more numbers are needed to find their LCM
Since 80 is a multiple of 2, the LCM is 80.
That's the difference of the monomials' squares. If the two numbers are "a" and "b" then (a + b)(a - b) = a^2 - b^2 where ^ means "to the power of".
If you mean 2 times 2, then no, but 2 and 2x are monomials.
You need at least two numbers to find an LCM.