This is similar to the often-used method to find the LCM of 2 numbers: you have to factor each monomial, and eliminate duplicate factors (factors that appear in both terms). An example might make this clearer.
LCM of x2 + 5x, and x2 + 6x + 1
Factoring each: x(x+5), and (x+1)(x+5)
Multiply all the factors, but use the common factor (x+5) only once: x(x+5)(x+1)
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LCM[(13b3)3, 7b2] = LCM[2197b9, 7b2] = 2197*7*b9 = 15379*b9
lcm(8, 9) = 72. 8 = 2^3 9 = 3^2 lcm = 2^3 x 3^2 = 72
To find the Least Common Multiple (LCM) of 8, 18, and 24, we first need to find the prime factorization of each number. The prime factorization of 8 is 2^3. The prime factorization of 18 is 2 * 3^2. The prime factorization of 24 is 2^3 * 3. To find the LCM, we take the highest power of each prime factor that appears in any of the numbers. So the LCM of 8, 18, and 24 is 2^3 * 3^2 = 72.
First you Prime Factorize the two (or more) numbers. The LCM of the two (or more) numbers must contain all the prime factors of the two (or more) numbers that made it. To find the LOWEST common multiple, for each prime factor, find from one of the numbers where the prime factor has the highest power. The highest powers of each prime multiply together to form the LCM of the numbers. e.g. LCM of 36 and 24 36 = (2^2)(3^2) 24 = (2^3)3 LCM = (2^3)(3^2) = 72
To find the Least Common Multiple (LCM) of 12, 9, and 15, we first need to find the prime factorization of each number. The prime factorization of 12 is 2^2 * 3, the prime factorization of 9 is 3^2, and the prime factorization of 15 is 3 * 5. To find the LCM, we take the highest power of each prime factor that appears in any of the numbers: 2^2 * 3^2 * 5 = 180. Therefore, the LCM of 12, 9, and 15 is 180.