This is similar to the often-used method to find the LCM of 2 numbers: you have to factor each monomial, and eliminate duplicate factors (factors that appear in both terms). An example might make this clearer.
LCM of x2 + 5x, and x2 + 6x + 1
Factoring each: x(x+5), and (x+1)(x+5)
Multiply all the factors, but use the common factor (x+5) only once: x(x+5)(x+1)
LCM[(13b3)3, 7b2] = LCM[2197b9, 7b2] = 2197*7*b9 = 15379*b9
lcm(8, 9) = 72. 8 = 2^3 9 = 3^2 lcm = 2^3 x 3^2 = 72
To find the Least Common Multiple (LCM) of 16, 32, and 36, we need to first factorize each number. The prime factors of 16 are 2^4, 32 is 2^5, and 36 is 2^2 * 3^2. To find the LCM, we take the highest power of each prime factor that appears in any of the numbers, which gives us 2^5 * 3^2 = 288. Therefore, the LCM of 16, 32, and 36 is 288.
First you Prime Factorize the two (or more) numbers. The LCM of the two (or more) numbers must contain all the prime factors of the two (or more) numbers that made it. To find the LOWEST common multiple, for each prime factor, find from one of the numbers where the prime factor has the highest power. The highest powers of each prime multiply together to form the LCM of the numbers. e.g. LCM of 36 and 24 36 = (2^2)(3^2) 24 = (2^3)3 LCM = (2^3)(3^2) = 72
To find the Least Common Multiple (LCM) of 12, 9, and 15, we first need to find the prime factorization of each number. The prime factorization of 12 is 2^2 * 3, the prime factorization of 9 is 3^2, and the prime factorization of 15 is 3 * 5. To find the LCM, we take the highest power of each prime factor that appears in any of the numbers: 2^2 * 3^2 * 5 = 180. Therefore, the LCM of 12, 9, and 15 is 180.
The least common multiple (LCM) of two monomials is the smallest monomial that is a multiple of both monomials. To find the LCM of 26ab^2 and 28ac^3, we need to identify the highest power of each variable that appears in either monomial. The LCM will then be the product of these highest powers, along with any remaining unique factors. In this case, the LCM of 26ab^2 and 28ac^3 is 364a^1b^2c^3.
72(d^3)(e^2)72 is the LCM of 24 and 36.d^3 is the LCM of d and d^3.e^2 is the LCM of e^2 and e.
72y^3
72y
Example: 3x4y2 and 9x3y5 Treat the whole numbers normally. The LCM of 3 and 9 is 9. Choose the highest value of the variables. In this case, the LCM is 9x4y5
72y^3
96a^4
LCM[(13b3)3, 7b2] = LCM[2197b9, 7b2] = 2197*7*b9 = 15379*b9
The GCF is 7y^2.
You need at least two numbers to find an LCM.
Let's try one. 30x2y3z4 - 42x4y5z2 Do the numbers first. Factor them. 2 x 3 x 5 = 30 2 x 3 x 7 = 42 Combine the factors, eliminating duplicates. 2 x 3 x 5 x 7 = 210 For the variables, select the highest exponent. The LCM of the above expression is 210x4y5z4
Since 16x3 is a multiple of 4x, it is automatically the GCF of this problem.