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Given:In a triangle ABC in which EF BC

To prove that:AE/EB=AF/FC

Construction:Draw EX perpendicular AC and FY perpendicular AB

Proof:taking the ratios of area of triangle AEF and EBF and second pair of ratio of area of triangle AEF and ECF.

We get AE/EB and AF/FC

we know that triangle lie b/w sme and same base is equal in area

therefore area of EBF I equal to area of ECF

therefore AE/EB=AF/FC

HENCE PROVED

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14y ago

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More answers

depends on what you have....

one way is to see that the the triangles share two same angles, and one side with equal length...

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13y ago
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They need no be. You cannot prove an assertion that need not be satisfied.

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11y ago
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A diagonal separates the parallelogram into?

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It appears from the name of the HL Theorem that you actually need to know that only two parts of two triangles are congruent in order to prove two triangles congruent Is this the case?

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What is the difference between a theorem and postulate?

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